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| Mathematics Magazine for Grades 1-12 |
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| 11-2004 |
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Grade 3
Theory:Multiplying by 100s
Solutions from the Previous Issue:Calculate: 1. (16 – 8) × (27 ÷ 3 ) = Solution: (16 – 8) × (27 ÷ 3 ) = 8 × 9
= 72 2. (51 – 9) ÷ (12 – 5) = Solution: (51 – 9) ÷ (12 – 5) = 42 ÷
7 = 6 3. (54 – 9) × (72 ÷ 9) = Solution: (54 – 9) × (72 ÷ 9) = 45 × 8
= 360 4. (63 ÷ 9) × (86 – 78) = Solution: (63 ÷ 9) × (86 – 78) = (63 ÷ 9) × (86 – 78) = 7 × 8 = 56 Proposed Exercises:
Complete the following table
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Read more on the written version of the publication |
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