Mathematics Magazine for Grades 1-12  

Grade 4

Theory: 

Names of Polygons

Solutions from the Previous Issue:

Calculate: 

1.        33 [1 + 34 (3 5 + 4 2)] =

Solution:

33 [1 + 34 (3 5 + 4 2)] =

33 [1 + 34 (15 + 2)] =

33 (1 + 34 17) =

33 (1 + 2) =

33 3 = 11

2.        15 + [30 (6 5 - 15) + 1]  3 =

Solution:

15 + [30 (6 5 - 15) + 1]  3 =

15 + [30 (30 - 15) + 1]  3 =

15 + (30 15+ 1)  3 =

15 + (2+ 1)  3 =

15 + 3  3 =

15 + 1  = 16

3.        [10 + 2(3 3 + 9  3)] 9 =

Solution:

[10 + 2(3 3 + 9  3)] 9 =

[10 + 2(1  + 3)] 9 =

(10 + 8) 9 =

18 9 = 2

4.        [10 + 2(3 3 + 9 3)] 9 - 2 =

Solution:

[10 + 2(3 3 + 9 3)] 9 - 2 =

[10 + 2(1 + 3)] 9 - 2 =

(10 + 8) 9 - 2 =

18 9 - 2 =

2 - 2 = 0

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